Algorithm
lc372_超级次方
思路:快速幂算法…n * log(k)
链接:https://leetcode-cn.com/problems/super-pow/solution/chao-ji-ci-fang-by-leetcode-solution-ow8j/
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class Solution {
const int MOD = 1337;
int pow(int x, int n) {
int res = 1;
while (n) {
if (n % 2) {
res = (long) res * x % MOD;
}
x = (long) x * x % MOD;
n /= 2;
}
return res;
}
public:
int superPow(int a, vector<int> &b) {
int ans = 1;
for (int i = b.size() - 1; i >= 0; --i) {
ans = (long) ans * pow(a, b[i]) % MOD;
a = pow(a, 10);
}
return ans;
}
};
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