ARST打卡第275周

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class Solution {
public:
    int maxUncrossedLines(vector<int>& nums1, vector<int>& nums2) {
        int m = nums1.size(), n = nums2.size();
        vector<vector<int>> dp(m + 1, vector<int>(n + 1));
        for (int i = 1; i <= m; i++) {
            int num1 = nums1[i - 1];
            for (int j = 1; j <= n; j++) {
                int num2 = nums2[j - 1];
                if (num1 == num2) {
                    dp[i][j] = dp[i - 1][j - 1] + 1;
                } else {
                    dp[i][j] = max(dp[i - 1][j], dp[i][j - 1]);
                }
            }
        }
        return dp[m][n];
    }
};

// 链接：https://leetcode.cn/problems/uncrossed-lines/solutions/787955/bu-xiang-jiao-de-xian-by-leetcode-soluti-6tqz/